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Lenovo’s Moto Z with Octa-core 1.8GHz Chipset Passes through TENAA

by Jed John 0

It’s been just a few days after the Lenovo Moto Z Play passed through TENAA, revealing the specs and images of the device, and now the Moto Z has also been spotted on the Telecommunications authority TENAA’s website. Both smartphones are expected to be available this month and they both have been certified ahead of their foray into the market.

Moto Z

The Moto Z and Moto Z Play have featured in numerous leaks and renders, so their expected specs and what they both look like is not hidden. The TENAA listing just goes to confirm the rumored specs of the China version of both smartphones.

moto z

The Moto Z carried the model number XT1650-05 on TENAA and is shown to have a somewhat similar design style with the Moto Z Play, save for some few features which differentiate the Moto Z from the higher end Moto Z Play. The positioning of the front camera sensors is different on the two smartphones. Also, the 3.5mm audio jack is notably absent on the phone.

moto z TENAA

The TENAA listing reveals the Moto Z as featuring a processor clocked at 1.8GHz , likely to be the 2.15GHz Snapdragon 820 chipset with a lowered clock frequency. There is also a 4GB RAM and 64GB of expandable storage on the flagship device. The device is also listed as packing a 2480mAh battery, a little lower than the 2600mAh earlier rumored. There is also a 5.5-inch 2K display, with an ultra thin and lightweight build. The entire device has a dimension of 75.3 × 155.3 × 5.2 mm and weighs just 138 g. In addition, the Moto Z is listed to have a 13MP camera at the back and a 5MP camera up front as well as having dual-SIM and full network support.

Read More: Lenovo announces September 6 launch date for Moto Z in China

The Moto Z is expected to be formally launched in China on September 6, and the China edition of both the Z and Z Play smartphones are expected to feature the One UI operating system.

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