Buy Leagoo Power 5 Smartphone For Only $199.99 On Banggood; Get Free Order Giveaway!

by Vinay Patel 0

Leagoo took the wraps off its long-awaited Power 5 smartphone during MWC2018, which took place in Barcelona. As expected, the phone became an instant hit among smartphone lovers.

Backed by a massive 7000mAh battery, the Power 5 smartphone demonstrated Leagoo’s strategic focus on making phones that carry big batteries. Bearing the Power 5’s skyrocketing popularity in mind, Banggood is doling out a big discount on its retail price, but that’s not all.

The Leagoo Power 5 smartphone would normally set you back $229.99, but Banggood will be selling it at a slashed price of just $199.99 for a limited period of time. As if that weren’t enough, the Chinese online store that guarantees the best bang for your buck is also handing out Free Order Giveaway.

Banggood will be randomly choosing a couple of free orders from people who buy the Power 5 smartphone during the pre-sell period, which kicked off on July 9th and will run until July 15th. The site will announce all winners on July 16th.


The Power 5 is equipped with a broad range of awe-inspiring specs and features that makes it an overwhelming smartphone. First off, the phone sports a mammoth 5.99 inches IPS, LCD FHD+ (1080 x 2160 pixels) display.

The Power 5 smartphone packs a MediaTek Helio P23 MT6763V processor along with an ARM Mali-G71 MP2 GPU, under the hood. It offers 6GB of RAM and a hearty 64GB of onboard storage (expandable up to 128GB).

On the photography front, the Power 5 features the SONY CMOS that allows it to capture even tiny details. It boasts an extra-wide f/2.2 aperture, paired with a customized 1/3.06-inch sensor. The phone combines multiple frames into one 65-megapixel shot with unparalleled definition and detail.

If you’re interested in taking advantage of the discount and grab the Free Order Giveaway, head straight to this link without wasting time. Note that the Leagoo Power 5 Free Order Giveaway will be allocated on a first come, first serve basis.